**Simplification questions (1-10) Set-119**

**For NICL Exams April 2015**

1)
The number of prime numbers in (25)13 * (10)7 * (27)5 is?

A)
25

B)
32

C)
55

D)
42

2)
what will be the remainder when (29)36 is divided by 28?

A)
0

B)
1

C)
29

D)
5

3)
what is the difference in intrinsic value and local value of 6 in 8631

A)
496

B)
594

C)
725

D)
122

4)
Replace the * in the number 6* 106 by a suitable digit so that the number
formed is exactly

divisible
by 11?

A)
2

B)
8

C)
5

D)
12

5)
A number is greater than 3 but less than 8. Also the number is greater than 6
but less than 10

What
is the number?

A)
7

B)
10

C)
5

D)
3

6)
The number that is nearest to 2160 and exactly divisible by 52 is?

A)
2132

B)
2148

C)
2184

D)
2177

7)
what will be the digit in the unit place in the product (3807)194 * (932)84?

A)
1

B)
9

C)
4

D)
2

8)
How many nimbers between 101 and 300 are divisible by both 3 and 5?

A)
14

B)
20

C)
107

D)
34

9)
There is a number 8*20 which if multiplied by 6, the product is divisible by 8.
The digit replacing *

mark
is?

A)
4

B)
Any digit in between 0 and 9

C)
0

D]
2

10)
(1/3 – 1/4) is added to a number. From the sum so obtained, 1/3 of 1/4 is
subtracted and the

remainder
is (1/3+1/4). The number is:

A)
7/12

B)
1/12

C)
1/4

D) 2/4

**Answers:**

(1) C

(2) B

(3) B

(4) A

(5) A

(6) C

(7) C

(8) A

(9) B

(10) A

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